Question
identify the initial amount in the following exponential function y=2.3(1.32)x
Answers
Reiny
We write exponents in this fashion.
y=2.3(1.32)^x
"initial" means at the beginning, or mathematically when x = 0
y = 2.3(1.32)^0
= 2.3(1) = ....
y=2.3(1.32)^x
"initial" means at the beginning, or mathematically when x = 0
y = 2.3(1.32)^0
= 2.3(1) = ....
brittany
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