Asked by Natni
                The average scores of the last four tests taken by Mike is 86 marks. To raise the scores to 92 marks, at least how many times does Mike have to get 100 marks in a row?
Please help me to solve this one! Thanks a lot🙏
            
        Please help me to solve this one! Thanks a lot🙏
Answers
                    Answered by
            Bosnian
            
    The average scores of the last four tests taken by Mike is 86 marks mean:
( x1 + x2 + x3 + x4 ) / 4 = 86
multiply moth sides by 4
x1 + x2 + x3 + x4 = 86 ∙ 4
x1 + x2 + x3 + x4 = 344
Mike have total 344 marks
When x times Mike get 100 marks awerage will be:
( 344 + x ∙ 100 ) / ( 4 + x ) = 92
multiply moth sides by 4 + x
344 + 100 x = 92 ∙ ( 4 + x )
344 + 100 x = 92 ∙ 4 + 92 ∙ x
344 + 100 x = 368 + 92 x
Subtract 92 x from both sides
344 + 100 x - 92 x = 368 + 92 x - 92 x
344 + 8 x = 368
Subtract 344 from both sides
344 + 8 x - 344 = 368 - 344
8 x = 24
x = 24 / 8 = 3
Proof:
The average scores after 4 + x = 4 + 3 = 7 tests will be:
( x1 + x2 + x3 + x4 + 100 + 100 + 100 ) / 7 =
( 344 + 300 ) / 7 = 644 / 7 = 92
    
( x1 + x2 + x3 + x4 ) / 4 = 86
multiply moth sides by 4
x1 + x2 + x3 + x4 = 86 ∙ 4
x1 + x2 + x3 + x4 = 344
Mike have total 344 marks
When x times Mike get 100 marks awerage will be:
( 344 + x ∙ 100 ) / ( 4 + x ) = 92
multiply moth sides by 4 + x
344 + 100 x = 92 ∙ ( 4 + x )
344 + 100 x = 92 ∙ 4 + 92 ∙ x
344 + 100 x = 368 + 92 x
Subtract 92 x from both sides
344 + 100 x - 92 x = 368 + 92 x - 92 x
344 + 8 x = 368
Subtract 344 from both sides
344 + 8 x - 344 = 368 - 344
8 x = 24
x = 24 / 8 = 3
Proof:
The average scores after 4 + x = 4 + 3 = 7 tests will be:
( x1 + x2 + x3 + x4 + 100 + 100 + 100 ) / 7 =
( 344 + 300 ) / 7 = 644 / 7 = 92
                    Answered by
            Natni
            
    Thanks a lot, it helps me a lot🙏
    
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