Question

Given that log3=0.4771 and log5=0.6690 and log2=0.3010. Without using tables or calculators evaluate log0.243
.243 = 243 / 100 = (3 * 81) / (10 * 10) = 3^5 / (2^2 * 5^2)

log(0.243) = 5log(3) - 2[log(2) + log(5)]

FYI ... log(5) = 0.6990
answer

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