Asked by Abdullahi fatimah

P is 49km away from q on a bearing of 135°.z is 64km away from R on a bearing of 225°find the distance of z from q and bearing of z from q
Answered by Abdullahi fatimah
I need an answer I don't no how to solve it
Answered by oobleck
since you have not given any relation between PQ and ZR there is no way to figure this out.
Answered by henry2,
If you mean Z is 64km from P:
ZQ = QP + PZ.
ZQ = 49[135o] + 64[225o],
X = 49*sin135 + 64*sin225 = -10.61 km.
Y = 49*Cos135 + 64*Cos225 = -79.90 km.
ZQ = -10.61 - 79.9i = 80.6km[7.56o] W. of S. = 80.6km[187.6o] CW.
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