Asked by Iz
A woman gives birth to a set of fraternal twins: a girl and a boy. She also passes on a color-blindness gene. Which of the children is more likely to be color-blind? I think the answer is B.
A. The girl is more likely to be color-blind from birth
B. The boy is more likely to be color-blind from birth
C. The girl will never be color-blind because the gene came from her mother
D. The boy will never be color-blind because the gene came from his mother
A. The girl is more likely to be color-blind from birth
B. The boy is more likely to be color-blind from birth
C. The girl will never be color-blind because the gene came from her mother
D. The boy will never be color-blind because the gene came from his mother
Answers
Answered by
Autumn
Yes, B is correct.
Colorblindness is caused by a recessive gene on the X chromosome. Females usually have two X chromosomes, while males usually only have one X chromosome and one Y chromosome. This means that females need two defective X chromosomes to catch colorblindness, but males only need one.
Colorblindness is caused by a recessive gene on the X chromosome. Females usually have two X chromosomes, while males usually only have one X chromosome and one Y chromosome. This means that females need two defective X chromosomes to catch colorblindness, but males only need one.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.