[ ( 2ˣ ) -7 )² = 1
Take the square root of both sides.
2ˣ - 7 = ±1
You must solve two equations:
2ˣ - 7 = -1 and 2ˣ - 7 = 1
1.)
2ˣ - 7 = -1
Add 7 to both sides
2ˣ - 7 + 7 = -1 + 7
2ˣ = 6
Take the logarithm of both sides.
x ∙ log ( 2 ) = log ( 6 )
x = log ( 6 ) / log ( 2 ) = 2.5849625
2.)
2ˣ - 7 = 1
Add 7 to both sides
2ˣ - 7 + 7 = 1 + 7
2ˣ = 8
Take the logarithm of both sides.
x ∙ log ( 2 ) = log ( 8 )
x = log ( 8 ) / log ( 2 ) = 3
Solve: ((2^x)-7)^2 = 1
The answer should be x = 2.58 (3 s.f.) or x = 3 but I have no idea how to get there. Thanks in advance!
1 answer