Question
An airplane needs to head due north, but there is a wind blowing from the southwest at 85 km/hr. The plane flies with an airspeed of 550 km/hr. To end up flying due north, how many degrees west of north will the pilot need to fly the plane? Round to the nearest tenth.
Answers
R_scott
85 kph * sin
(45º) = 550 kph * sin(Θ)
Θ is the angle west of north
(45º) = 550 kph * sin(Θ)
Θ is the angle west of north