Asked by Marinoel
In such an experiment 25CM³of 0.2M of sodium carbonate neutralises 50cm of tje Hydrochloric acid what is the morlarity of the acid
Answers
Answered by
bobpursley
I dont know what 25CMP is. If you mean 25 cm^3
Normality acid(volume)=Normalitybase (volume)
Na*50=2*.2*25
then Normality of acid is .2
and then Molarity is .2M
Normality acid(volume)=Normalitybase (volume)
Na*50=2*.2*25
then Normality of acid is .2
and then Molarity is .2M
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