Asked by Remie
Human beings can typically detect a difference in sound level of 2.0 dB. What is the ratio of the amplitudes of two sounds whose levels differ by this amount. Is this even solvable?
Answers
Answered by
bobpursley
what is 10^.2?
Answered by
MAZ-31
20 log (A1/A2) = 2
log(A1/A2) = 0.1
A1/A2 = 10^(0.1) = 1.2589
log(A1/A2) = 0.1
A1/A2 = 10^(0.1) = 1.2589
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