Asked by Berhan
Asimple machin has an efficiency of 0.75 and a velocity ratio of 12. What the load that can be moved if an effort of 100N is applied
Answers
Answered by
henry2,
L = Load.
E = Effort = 100 N.
Vr = Velocity ratio = 12.
0.75 = L/E * 1/Vr.
0.75 = L/100 * 1/12,
L = 0.75 * 1200 = 900 N.
E = Effort = 100 N.
Vr = Velocity ratio = 12.
0.75 = L/E * 1/Vr.
0.75 = L/100 * 1/12,
L = 0.75 * 1200 = 900 N.