Asked by Oakley
When a chemist burns hydrogen sulfide according to the reaction below she finds that the reaction releases heat. (It is exothermic.)
2H2S(g) + 3O2(g) 2SO2 + 2H2O(g)
The enthalpy of the reaction DH = -1037 kJ. What is the enthalpy change per gram of hydrogen sulfide ?
2H2S(g) + 3O2(g) 2SO2 + 2H2O(g)
The enthalpy of the reaction DH = -1037 kJ. What is the enthalpy change per gram of hydrogen sulfide ?
Answers
Answered by
Doc48
Fm equation 2 moles H2S = 2moles(34 g/mole) = 68 g H2S => -1037 Kj => 1 g H2s => (-1037/68) Kj/g = -15.25 Kj/g
Answered by
DrBob222
Hi Doc48. Several days ago you and anonymous made comments on an answer I gave and I resp;onded to the two of you but no answer from either. Here is the question. It now is far away on page 13 and of course continues to move further away. Anyway, here is the link. Will you please respond to my latest response.and it would be copnvenient if you made that response t tyhis site. Thank you.
https://www.jiskha.com/questions/1790701/A-25-0-mL-sample-of-a-0-100-M-solution-of-aqueous-trimethylamine-is-titrated-with#1850477
https://www.jiskha.com/questions/1790701/A-25-0-mL-sample-of-a-0-100-M-solution-of-aqueous-trimethylamine-is-titrated-with#1850477
Answered by
Anonymous
I should have clarified. I agree with Doc48 and I just assumed you were leaving work for the individual who posted the question to do on his or her own. I was.just agreeing with Doc48's assessment.
Answered by
DrBob222
To anonymous--Thank you for clarifying that. I appreciate it. I thought I had lost it. :-)
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