Asked by Alice
Evaluate Σ from n=1 to infinity of 3/2^n-1
a) 12
b) 6
c) 3
d) 0 ----> my answer. Can you check for me, please? Thanks in advance
a) 12
b) 6
c) 3
d) 0 ----> my answer. Can you check for me, please? Thanks in advance
Answers
Answered by
oobleck
you just have a geometric series where
a = 3
r = 1/2
S = 3/(1 - 1/2) = 6
The nth term converges to zero, but the sum does not
a = 3
r = 1/2
S = 3/(1 - 1/2) = 6
The nth term converges to zero, but the sum does not
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.