Asked by Cally
What mass of Pb(NO3)2,would be required to yeild 9g of PbCl2,on d addition of excex NaCl?Pb=207,N=14,O=16,Na=23,Cl=35.5
Answers
Answered by
bobpursley
Pb(NO3)2 + 2NaCl>>PbCl2 + 2NaNO3(aq)
so, moles Pb(NO3)2 = moles PbCl2
Moles PbCl2= 9g/(783)
MassPb(NO3)2= molesPbCl2*(molemass leadII nitrate).
so, moles Pb(NO3)2 = moles PbCl2
Moles PbCl2= 9g/(783)
MassPb(NO3)2= molesPbCl2*(molemass leadII nitrate).
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.