Asked by Plz help me I am mental retarted
Adam mixes the letters r e a d i n g s and a thoroughly without looking Alan draws one letter expressed as a fraction decimal and percentage what is the probability that Alan will not select a constant
9/5 1.8 18%
9/4, 2.25, 22.5%
4/9, 0.44 for, 44.4%
Five nights, 0.556, 5 5.6%
9/5 1.8 18%
9/4, 2.25, 22.5%
4/9, 0.44 for, 44.4%
Five nights, 0.556, 5 5.6%
Answers
Answered by
Plz help me I am mental retarted
5/9
Answered by
Reiny
Since there are no constants in "r e a d i n g s"
The prob(picking a constant) = 0
and the prob(not picking a constant) = 1
If you meant "consonants" , I count 5 consonants, and 3 vowels
since "no consonant" implies you want a vowel ......
The prob(picking a constant) = 0
and the prob(not picking a constant) = 1
If you meant "consonants" , I count 5 consonants, and 3 vowels
since "no consonant" implies you want a vowel ......
Answered by
kind of a commenter I guess
I don't know, my brain is the size of a nucleus
Answered by
Anonymous
ummmm what
Answered by
hange zoe
No, consonants are letters like, K, L, M, P, S, etc.
Vowels are the letters, A, E, I, O, U.
If you want to find the probability that you will NOT get a consonant, just count how many vowels there are.
There are 9 letters in total, with 5 consonants, and 4 vowels.
The answer should be 4/9; or .444 and 44.4%
Vowels are the letters, A, E, I, O, U.
If you want to find the probability that you will NOT get a consonant, just count how many vowels there are.
There are 9 letters in total, with 5 consonants, and 4 vowels.
The answer should be 4/9; or .444 and 44.4%
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