An elastic spring of force constant 20Nm is stretched through 8m within its elastic limit calculate the energy stored on thestring?

energy= force*distance=20*8 Nm

To calculate the energy stored in the spring, you can use the formula:

Elastic potential energy (E) = (1/2) * k * x^2

Where:
E is the energy stored in the spring
k is the force constant of the spring
x is the displacement from the equilibrium position

In this case, the force constant (k) is given as 20 Nm, and the displacement (x) is given as 8 m.

Plugging these values into the formula:

E = (1/2) * 20 Nm * (8 m)^2

E = (1/2) * 20 Nm * 64 m^2

E = 640 Nm

Therefore, the energy stored in the spring is 640 Nm.

To calculate the energy stored in a spring, you can use the formula:

E = (1/2) * k * x^2

Where:
E is the energy stored in the spring,
k is the force constant (also known as the spring constant),
x is the displacement of the spring from its equilibrium position.

In this case, the force constant (k) is given as 20 Nm, and the displacement (x) of the spring is given as 8 m.

Let's substitute these values into the formula:

E = (1/2) * 20 Nm * (8 m)^2

First, calculate the square of 8:

E = (1/2) * 20 Nm * 64 m^2

Next, multiply the force constant by the square of the displacement:

E = 640 Nm * m^2

Finally, simplify the units by removing m^2:

E = 640 Nm

So, the energy stored in the spring is 640 Nm.