Asked by BIZHATOCOTO
PQR is a triangle and PX is perpendicular to QR at X.
Given that PR= 6cm, RX=4cm and RQ=9cm, calculate PQ.
Leave your answer in surd form?
Given that PR= 6cm, RX=4cm and RQ=9cm, calculate PQ.
Leave your answer in surd form?
Answers
Answered by
Reiny
Did you make your sketch??
I get PX^2 + 4^2 = 6^2
PX =
now in the other triangle:
PQ^2 = 5^2 + PX^2 , but you know PX^2, so its easy from here
I get PX^2 + 4^2 = 6^2
PX =
now in the other triangle:
PQ^2 = 5^2 + PX^2 , but you know PX^2, so its easy from here
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