Question
120 cm^3 of NH3 gas was prepared and collected at R.T.P. All the NH3 gas was reacted with H3PO4 according to the following reaction
3NH3(g) + H3PO4(aq)= (NH4)3 PO4(aq)
calculate:
1. the number of moles of NH3 that was collected
2. the mass of (NH4)3 PO4 obtained.
[N=14, O=16, P=31, H=1; molar gas volume at R.T.P. =24000 cm^3 ]
3NH3(g) + H3PO4(aq)= (NH4)3 PO4(aq)
calculate:
1. the number of moles of NH3 that was collected
2. the mass of (NH4)3 PO4 obtained.
[N=14, O=16, P=31, H=1; molar gas volume at R.T.P. =24000 cm^3 ]
Answers
DrBob222
1. Use PV = nRT and solve for n = numer of mols.
2. mols NH3 from 1 = mols (NH4)3PO4
Then g (NH4)3PO4 = mols x molar mass
Post your work if you get stuck.
2. mols NH3 from 1 = mols (NH4)3PO4
Then g (NH4)3PO4 = mols x molar mass
Post your work if you get stuck.