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Determine whether the sequence converges or diverges. If it converges, find the limit. An=((-2)^n)/n!Asked by Anonymous
Determine whether the sequence converges or diverges. If it converges, find the limit. an =
cos^2(n)/3^n
cos^2(n)/3^n
Answers
Answered by
oobleck
clearly it converges, since |cos(x)| < 1 so the terms approach zero as x gets huge, since 3^x gets huge. That is,
an < 1/3^n
an < 1/3^n