Asked by jake

please help need to get this work in for tomorrow and im lost
A sample of argon has a volume of 6.0 dm3 and the pressure is 0.91 atm. If the final

temperature is 32° C, the final volume is 5.7 L, and the final pressure is 800 mmHg, what

was the initial temperature of the argon?
Answered by bobpursley
general gas equation
P1V1/T1=P2V2/T2
change your temps to kelvins, solve for t1, notice dm^3 is same as Liter L, convert .91 atm to mmgh (P2=.91*760 mmHg

T1=P1V1T2/P2V2
Answered by Claudette
Is that a solution?
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