Question

solubility product of silver iodate is 1.9×10^-15 at 25°c what is the molar solubility of silver iodide in water

Answer 1

.................AgIO3 ==> Ag^+ + IO3^-
I..............solid..............0...........0
C.............solid..............x............x
E.............solid..............x.............x

Ksp = (Ag^+)(IO3^-)
Substitute the E line into Ksp expression and solve for x = (Ag^+) = (IO3^=) = (AgCl)

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