Asked by tom

FInd the integral of the infinite series of (2x)^n / n^2

I got (2x)^(n+1) / 2n^2(n+1)
is this right


∫ from 0 to ∞ ∑ (2x)^n / n^2

Answered by oobleck
almost. You forgot the chain rule:
∫(2x)^n/n^2 = (2x)^(n+1)/(n^2 * (n+1)*2)
Answered by tom
That's literally what i had
Answered by oobleck
You are correct, but we were both wrong. It should have been
(2x)^(n+1)/(n^2 * (n+1)) * 2
Answered by tom
why that way
There are no AI answers yet. The ability to request AI answers is coming soon!