Asked by kristy
If a 54 pound boy falls off the top of the grand canyon which is 5996 feet deep, how many seconds will it take for him to hit the bottom?
Answers
Answered by
R_Scott
his weight is not a factor
the free fall equation is ... h = -1/2 g t^2 + Vo t + Ho
... h is height , g is gravitational acceleration
... Vo is initial velocity , Ho is initial height
h = 0 at the bottom , g = 32 ft/s^2
0 = -16 t^2 + 0 t + 5996
solve the quadratic for t
the free fall equation is ... h = -1/2 g t^2 + Vo t + Ho
... h is height , g is gravitational acceleration
... Vo is initial velocity , Ho is initial height
h = 0 at the bottom , g = 32 ft/s^2
0 = -16 t^2 + 0 t + 5996
solve the quadratic for t
Answered by
henry2,
0.5g*t^2 = 5996.
16t^2 = 5996,
16t^2 = 5996,
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