Asked by Thapelo
the minimum distance that required to stop a car moving at 35.0 mi/h is 40 ft.
(a) express this speed and distance in km/h.
(b) what is the minimum stoping distance of a car moving at 70 mi/h,assuming the same rate of acceleration?express your answer in km.
(a) express this speed and distance in km/h.
(b) what is the minimum stoping distance of a car moving at 70 mi/h,assuming the same rate of acceleration?express your answer in km.
Answers
Answered by
henry2,
a. Vo = 35mi/h * 1.6km/mi = 56 km/h.
b. V = 35mi/h * 5280ft/mi * 1h/3600s = 51.3 ft/s.
V^2 = Vo^2 + 2a*d = 0.
51.3^2 + 2a*40 = 0,
a = -33 ft/s^2.
Vo = 70/35 * 51.3ft/s = 102.6 ft/s.
V^2 = Vo^2 + 2a*d = 0.
(102.6)^2 + (-66)d = 0,
d = 160 ft. = 48.3 m. = Stopping distance.
b. V = 35mi/h * 5280ft/mi * 1h/3600s = 51.3 ft/s.
V^2 = Vo^2 + 2a*d = 0.
51.3^2 + 2a*40 = 0,
a = -33 ft/s^2.
Vo = 70/35 * 51.3ft/s = 102.6 ft/s.
V^2 = Vo^2 + 2a*d = 0.
(102.6)^2 + (-66)d = 0,
d = 160 ft. = 48.3 m. = Stopping distance.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.