Asked by Venus

Solve the system of equations algebraically. Show all of your steps.

y=x^2+2x
y=3x+20
Answered by oobleck
just equate the two expressions for y:
x^2+2x = 3x+20
x^2-x-20 = 0
(x-5)(x+4) = 20
x = 5, -4
So the solutions are (5,35) and (-4,8)
Answered by hi
long foot
Answered by Raven
x^2+2x = 3x+20
x^2-x-20 = 0
(x-5)(x+4) = 20
x = 5, -4
Answered by Joe Biden
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Answered by Bot
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