Asked by Mai
1.
a) On Wednesday, Harry sold 3 times as many candy bars as on Tuesday. On Thursday, he sold 5 times as many bars as on Wednesday. He sold a total of 152 candy bars. How many did he sell each day?
b) Bill has 5 times as many baseball cards as Fred. Tim has 3 fewer than 4 times as many baseball cards as Fred. In all they have 167 baseball cards. How many does each have?
2.
a) The length of a rectangle is 5 more than the width. The perimeter of the rectangle is 168 inches. Find the dimensions of the rectangle.
b) The length of a rectangle is twice the width. If the length is increased by 4 inches and the width is diminished by 1 inch, a new rectangle is formed whose perimeter is 198 inches. Fine the dimensions of the original rectangle.
I really don"t understand word problems can someone help me on how to make equations on these
a) On Wednesday, Harry sold 3 times as many candy bars as on Tuesday. On Thursday, he sold 5 times as many bars as on Wednesday. He sold a total of 152 candy bars. How many did he sell each day?
b) Bill has 5 times as many baseball cards as Fred. Tim has 3 fewer than 4 times as many baseball cards as Fred. In all they have 167 baseball cards. How many does each have?
2.
a) The length of a rectangle is 5 more than the width. The perimeter of the rectangle is 168 inches. Find the dimensions of the rectangle.
b) The length of a rectangle is twice the width. If the length is increased by 4 inches and the width is diminished by 1 inch, a new rectangle is formed whose perimeter is 198 inches. Fine the dimensions of the original rectangle.
I really don"t understand word problems can someone help me on how to make equations on these
Answers
Answered by
Reiny
In most of these you simply have to translate from English to Math.
I will do #2 b)
original rectangle:
"The length of a rectangle is twice the width"
since "width" is the reference , let the width be x inches
then the length must be 2x inches
new rectangle:
"the length is increased by 4" ---> length = 2x+4
"the width is diminished by 1" ----> width = x - 1
perimeter of new rectangle is 198 ----> twice the length + twice the width = 198
2(2x+4) + 2(x-1) = 198
4x + 8 + 2x - 2 = 198
6x = 192
x = 32
<b>original width = 32 inches
original length = 64 inches</b>
new width = 31
new length = 68
new perimeter = 2(31) + 2(68) = 198
My answer is correct
Follow my method, perhaps highlighting or underlining the important phrases to form your variables.
I will do #2 b)
original rectangle:
"The length of a rectangle is twice the width"
since "width" is the reference , let the width be x inches
then the length must be 2x inches
new rectangle:
"the length is increased by 4" ---> length = 2x+4
"the width is diminished by 1" ----> width = x - 1
perimeter of new rectangle is 198 ----> twice the length + twice the width = 198
2(2x+4) + 2(x-1) = 198
4x + 8 + 2x - 2 = 198
6x = 192
x = 32
<b>original width = 32 inches
original length = 64 inches</b>
new width = 31
new length = 68
new perimeter = 2(31) + 2(68) = 198
My answer is correct
Follow my method, perhaps highlighting or underlining the important phrases to form your variables.
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