Asked by Vernice
The first side of a triangle is 3 inches shorter than the second side, and 2 inches longer than the third side. How long is each side, if the triangle has a perimeter of 28 inches?
Answers
Answered by
Ms Pi_3.14159265358979
Sketch it out :)
One side is 3 shorter then the other, so you need x + 3 to reach the x side. The other side is x - 2, and the other side is x.
P = s + s + s
28 = x + x - 2 + x + 3
.
.
.
solve...
One side is 3 shorter then the other, so you need x + 3 to reach the x side. The other side is x - 2, and the other side is x.
P = s + s + s
28 = x + x - 2 + x + 3
.
.
.
solve...
Answered by
eatmyass
idk bro
Answered by
...
Third Side>First Side>Second Side
x-2>x>x+3
x+x+x+3+-2=3x+1
28-1=27
27/3=9
x=9
x+3=12
x-2=7
Answer: Third Side=7 First Side=9 Second Side=12
x-2>x>x+3
x+x+x+3+-2=3x+1
28-1=27
27/3=9
x=9
x+3=12
x-2=7
Answer: Third Side=7 First Side=9 Second Side=12
Answered by
...
woops it's meant to be x-2<x<x+3
Answered by
Cody
The second side of a triangle is 7 inches more than the first side. The third side is 4 inches less than 3 times the first. The perimeter is 28 inches.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.