Asked by KKK
How does 0-(1/81)-((te^9t)/81)+(9e^9t/81)=(-1/81)-0+0? Where does the 0 come from?
Answers
Answered by
oobleck
Hmmm. Some context would be nice.
if t=0 then ((te^9t)/81) = 0
But (9e^(9t)/81) = (9*1)/81 = 1/9
if t=0 then ((te^9t)/81) = 0
But (9e^(9t)/81) = (9*1)/81 = 1/9
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.