Asked by Connor Steelwood

Solve the system of equations
y=2x^2-3
y=3x-1
Answered by Reiny
2x^2-3 = 3x-1
2x^2 - 3x - 2 = 0
(2x + 1)(x - 2) = 0
x = -1/2 or x = 2

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