Asked by Anonymous
What force would be required for Steve to do as much work when he pushes at ϕ=40∘ as when he pushes in the ϕ=0 direction?
Answers
Answered by
bobpursley
force? What is 1/cos40?
forcedown*cos40*distance=force in direction distiance*distance
forcedown=force in direction/cos40
forcedown*cos40*distance=force in direction distiance*distance
forcedown=force in direction/cos40
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