Asked by lula
17. At what distance of separation, r, must two 5.87 x 10^-8 Coulomb charges be positioned in order for the repulsive force
between them to be 64.9 N? You must show your work for credit
between them to be 64.9 N? You must show your work for credit
Answers
Answered by
bobpursley
64.6=8.9e9*(5.87e-8)^2/d^2
d=5.87e-8 *(sqrt (8.9e9/64.6))=
pretty close...
d=5.87e-8 *(sqrt (8.9e9/64.6))=
pretty close...
Answered by
lula
after i did the problem i got the answer 7.6 x 10^-4 is this correct
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