Asked by lula

17. At what distance of separation, r, must two 5.87 x 10^-8 Coulomb charges be positioned in order for the repulsive force
between them to be 64.9 N? You must show your work for credit

Answers

Answered by bobpursley
64.6=8.9e9*(5.87e-8)^2/d^2
d=5.87e-8 *(sqrt (8.9e9/64.6))=

pretty close...
Answered by lula
after i did the problem i got the answer 7.6 x 10^-4 is this correct
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