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17. At what distance of separation, r, must two 5.87 x 10^-8 Coulomb charges be positioned in order for the repulsive force
between them to be 64.9 N? You must show your work for credit
6 years ago

Answers

bobpursley
64.6=8.9e9*(5.87e-8)^2/d^2
d=5.87e-8 *(sqrt (8.9e9/64.6))=

pretty close...
6 years ago
lula
after i did the problem i got the answer 7.6 x 10^-4 is this correct
6 years ago

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