Question
The diameter of a bicycle’s tires is 2.5 feet. How many revolutions of the tires does it take to travel 1 mild? Use 5280 feet = 1 mile. Round to the nearest tenth.?
Answers
for each revolution of the tire , the bicycle travels ... 2.5 π ft
revs = 5280 / (2 π)
revs = 5280 / (2 π)
n = numbrs of revolutions
Circumference of a tires:
C = d π = 2.5 π = 2.5 ∙ π = 2.5 ∙ 3.14159 = 7.853975 ft
n = 1 mile / C
n = 5280 / 7.853975 = 672.2710474633 revolutions
n = 672.3 revolutions
,
rounded to the nearest tenth.
Circumference of a tires:
C = d π = 2.5 π = 2.5 ∙ π = 2.5 ∙ 3.14159 = 7.853975 ft
n = 1 mile / C
n = 5280 / 7.853975 = 672.2710474633 revolutions
n = 672.3 revolutions
,
rounded to the nearest tenth.
10x-10=189+09=+7474=yu*yv
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