Asked by Kim
The diameter of a bicycle’s tires is 2.5 feet. How many revolutions of the tires does it take to travel 1 mild? Use 5280 feet = 1 mile. Round to the nearest tenth.?
Answers
Answered by
R_scott
for each revolution of the tire , the bicycle travels ... 2.5 π ft
revs = 5280 / (2 π)
revs = 5280 / (2 π)
Answered by
Bosnian
n = numbrs of revolutions
Circumference of a tires:
C = d π = 2.5 π = 2.5 ∙ π = 2.5 ∙ 3.14159 = 7.853975 ft
n = 1 mile / C
n = 5280 / 7.853975 = 672.2710474633 revolutions
n = 672.3 revolutions
,
rounded to the nearest tenth.
Circumference of a tires:
C = d π = 2.5 π = 2.5 ∙ π = 2.5 ∙ 3.14159 = 7.853975 ft
n = 1 mile / C
n = 5280 / 7.853975 = 672.2710474633 revolutions
n = 672.3 revolutions
,
rounded to the nearest tenth.
Answered by
Qasem I just want to see
10x-10=189+09=+7474=yu*yv
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.