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A company paid $110,000 for a new 18-wheeler. When it is 9 years old it will be worth $20,000. Using straight-line depreciation...Asked by Tyler
A company paid $150,000 for a new 18-wheeler. When it is 9 years old it will be worth $42,000. Using straight-line depreciation, the value of the truck in dollars, V, is a linear function of its age in years, n. Find the function and the value when the truck is 4 years old.
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Answered by
Reiny
Look at it as being given two ordered pairs , (0,150000) and (9,42000)
slope = (42000-150000)/(9-0) = -108000/9 = -12000
so value = V(n) = -12000n + b
but (0,150000) is the "y-intercept"
your function is
V(n) = -12000n + 150000
for the 2nd part, plug in n = 4
slope = (42000-150000)/(9-0) = -108000/9 = -12000
so value = V(n) = -12000n + b
but (0,150000) is the "y-intercept"
your function is
V(n) = -12000n + 150000
for the 2nd part, plug in n = 4
Answered by
henry2,
V = Vo - Vo*r*T = $42,000.
150,000 - 150,000*r*9 = 42,000.
1 - 9r = 0.28,
9r = 0.72,
r = 0.08/yr. = Annual depreciation rate.
V = Vo - Vo*r*T.
V = 150,000 - 150,000*0.08*4 = $102,000.
150,000 - 150,000*r*9 = 42,000.
1 - 9r = 0.28,
9r = 0.72,
r = 0.08/yr. = Annual depreciation rate.
V = Vo - Vo*r*T.
V = 150,000 - 150,000*0.08*4 = $102,000.
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