Asked by lolololol
Consider two circular swimming pools. Pool A has a radius of 18 feet, and Pool B has a diameter of 11.16 meters. Complete the description for which pool has a greater circumference. Round to the nearest hundredth for each circumference. 1 foot ≈ 0.305 meters
Answers
Answered by
lolololol
The diameter of Pool A is ...
meters. So, the diameter of Pool... is greater, and the circumference is... by...
meters.
Answered by
oobleck
just compare
18 to 11.16*3.28
or
18*0.305 to 11.16
18 to 11.16*3.28
or
18*0.305 to 11.16
Answered by
lolololol
thanks
Answered by
Anonymous
Identify the diameter of Pool A.
d = 2r
d = 2(18) Substitute 18 for r.
d = 36 ft
Convert from feet to meters. Use the ratio of 1 foot to 0.305 meters.
36 × 0.305 = 10.98
The diameter of Pool A is about 10.98 meters.
Use the formula to find the circumference of Pool A.
C = πd
C = π(10.98) Substitute 10.98 for d.
C ≈ 3.14(10.98) Substitute 3.14 for π.
C ≈ 34.48 Multiply. Round to the nearest hundredth.
The circumference of Pool A is about 34.48 meters.
Identify the diameter of Pool B.
d = 11.16 m
The diameter of Pool B is 11.16 meters.
Use the formula to find the circumference of Pool B.
C = πd
C = π(11.16) Substitute 11.16 for d.
C ≈ 3.14(11.16) Substitute 3.14 for π.
C ≈ 35.04 Multiply. Round to the nearest hundredth.
The circumference of Pool B is about 35.04 meters.
The circumference of Pool B is greater than the circumference of Pool A.
Find how much greater the circumference of Pool B is compared to the circumference of Pool A.
35.04 − 34.48 = 0.56
The circumference of Pool B is greater than the circumference of Pool A by about 0.56 meters.
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