Asked by paul
How many atom of oxygen are present in 8.8g of carbon(iv)oxide
Answers
Answered by
T.O.K
0.04
Answered by
Doc48
Moles CO2 = 8.8-g CO2/44g/mole CO2 = 0.20 mole CO2 x 6.02E23 molecules CO2/mole = 1.204E23 molecules CO2 in the 8.8-gram sample.
#atoms Oxy per CO2 molecule = 2
Therefore, #oxy atoms in 8.8-g CO2 = 1.204E23 molecules CO2 x 2 oxy molecules/CO2 molecule = 2.408E23 oxy atoms in the 8.8-g sample of CO2.
#atoms Oxy per CO2 molecule = 2
Therefore, #oxy atoms in 8.8-g CO2 = 1.204E23 molecules CO2 x 2 oxy molecules/CO2 molecule = 2.408E23 oxy atoms in the 8.8-g sample of CO2.
Answered by
Lack
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