Asked by Angel

1.)A proton moving with speed v enters a narrow (1.0 cm wide) region of magnetic field perpendicular to the direction of the proton's motion. As a result, the proton acquires a small component of speed perpendicular to its original direction of motion. This speed is much less than the original speed, and is measured to be 3.3 x10 ^5 m/s. The magnitude of the force on the proton is 1.8 x10 ^-18 N. What is the strength of the magnetic field?
Answered by bobpursley
Force=B*l*v You are given force, length, and velocity. solve for B
Answered by ERNANI
1.)A proton moving with speed v enters a narrow (1.0 cm wide) region of magnetic field perpendicular to the direction of the proton's motion. As a result, the proton acquires a small component of speed perpendicular to its original direction of motion. This speed is much less than the original speed, and is measured to be 3.3 x10 ^5 m/s. The magnitude of the force on the proton is 1.8 x10 ^-18 N. What is the strength of the magnetic field?
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