Asked by alissa
A chemical reaction is run in which 736 Joules of work is done by the system and the internal energy changes by -1370 Joules.
pls help me
pls help me
Answers
Answered by
DrBob222
I don't see a question.
Answered by
Doc48
I’m guessing you need the Rxn Enthalpy. It’s the only given data item missing for the 1st Law equation…
ΔU = q + w => q = ΔU – w = (-1370 J) – (- 736 J) = (-1370 + 736) J = - 634 Joules exothermic heat of rxn.
ΔU = -1370 Joules (given)
w = -736 Joules (expansion work)*
*expansion => system is working (pushing back) on the surroundings => w < 0.
*compression => surroundings working (compressing) on the system => w > 0.
ΔU = q + w => q = ΔU – w = (-1370 J) – (- 736 J) = (-1370 + 736) J = - 634 Joules exothermic heat of rxn.
ΔU = -1370 Joules (given)
w = -736 Joules (expansion work)*
*expansion => system is working (pushing back) on the surroundings => w < 0.
*compression => surroundings working (compressing) on the system => w > 0.
Answered by
Anonymous
ご投資にかかる手数料等およびリスクについて|お知らせ|企業・IR情報|株のことならネット証券会社【カブドットコム】
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.