If g(x)=(ax square root of 1-x)^2. Express g(10) in simplest form

If your expression mean:

g = a ∙ x ∙√ ( 1 - x )²

then

g(10) = a ∙ 10 ∙ √ ( 1 - 10 )² = 10 a ∙ √ ( - 9 )² = 10 a ∙ ( - 9 ) = - 90 a

g = [ a ∙ x ∙√ ( 1 - x ) ]²

then

g = [ a ∙ 10 ∙√ ( 1 - 10 ) ]² =

[ 10 a ∙√- 9 ) ]² =

( 10 a ∙ 3 i ² )=

(30 a ∙ i )² =

30² ∙ a² ∙ i² =

900 ∙ a² ∙ ( - 1 ) = - 900 ∙ a²

My typo

not

( 10 a ∙ 3 i ² )=

correct is

( 10 a ∙ 3 i )² =

yes , it was the second one and when I looked over it again I saw that I actually wrote 100a^2 on my paper but when I put in the question here I did 1000, I can't read my own handwriting. Thank you for explaining both ways.

To express g(10) in simplest form, let's go step by step.

We are given the function g(x) = (ax√(1-x))^2.

To find g(10), we substitute x with 10 in the function:

g(10) = (a(10)√(1-10))^2

Now, let's simplify this expression:

√(1-10) = √(-9)

The square root of a negative number is not defined in the real number system, so we cannot calculate this term further.

Therefore, we cannot simplify g(10) any further, and the expression remains g(10) = (a(10)√(1-10))^2.

It seems that there may be an error in the calculation you provided. Please double-check the problem statement or your calculations.