Question

which ordered pair is in the solution set of the system of equations shown below?
y^2-x^2+32=0
3y-x=0

I did
y^2-3y^2+32=0
y^2-9y^2=-32
8y^2=32
y^2=32/8
y^2=4
y=+/-2
x=3(2)=6
{2,6}
is this right? thank you

Answer 1

1. You got the variables turned around in your answer
2. What about the 2nd value of y ?

Your points are (6,2) and (-6,-2)

see:
www.wolframalpha.com/input/?i=plot+y%5E2-x%5E2%2B32%3D0,+3y-x%3D0