Asked by Klauus
The following graph models the height of a model rocket in feet measured over time in seconds.
a graph of a downward opening parabola. The x axis is labeled Time in seconds. The Y axis is labeled Height in feet. Points on the graph include starting point (negative 0.04, 0) (2.5, 103), and the ending point(5.04, 0).
How many seconds does it take for the rocket to reach the ground?
Enter your answer as a number, like this: 42.
Do not round your answer if it is a decimal.
I got the answer 2.54 from subtracting 2.5 from 5.04 because the seconds it takes to reach the ground cannot be negative which is why I didn't subtract 2.5 from 5.04 which equaled: -2.54. Unless it wants us to do addition which the answer would be 7.54 seconds.
Answers
Answered by
oobleck
no. You start measuring at time t=0
It took 5.04 seconds for the height to reach zero.
It took 5.04 seconds for the height to reach zero.
Answered by
Klauus
Wouldn't it take 5.08 seconds because it started at -0.004 seconds?
Answered by
oobleck
nothing happens before t=0
You launch the rocket, and 5.04 seconds later it lands.
It was launched from some initial nonzero height.
If it had been launched from the ground, it would have had to have happened 0.04 seconds earlier.
But it didn't.
You launch the rocket, and 5.04 seconds later it lands.
It was launched from some initial nonzero height.
If it had been launched from the ground, it would have had to have happened 0.04 seconds earlier.
But it didn't.
Answered by
jonathan
so whats the answer
Answered by
Shyann
5.04
Answered by
strawberrryy
thanks for the answer :D
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.