Asked by Emma
What is the difference in simplest form?
(n^2+3n+2)/(n^2+5n+6)-2n/(n+3)
A. (1-n)/(n+3)
B. 1/(n+3)
C. (n+1)/(n+3)
D. (n-1)/(n+3)
(n^2+3n+2)/(n^2+5n+6)-2n/(n+3)
A. (1-n)/(n+3)
B. 1/(n+3)
C. (n+1)/(n+3)
D. (n-1)/(n+3)
Answers
Answered by
Spring Allergies
I'm not very good at math, but I feels as though C would be your best bet. Don't choose this answer if you don'y feel comfortable with it. I don't want to give anybody wrong answers to where they fail. Good Luck! :)
Answered by
Reiny
(n^2+3n+2)/(n^2+5n+6) - 2n/(n+3)
= (n+2)(n+1)/( (n+3)(n+2)) - 2n/(n+3)
= (n+1)/(n+3) - 2n/(n+3) , now you have a common denominator
= (n+1 - 2n)/(n+3)
= (1 - n)/(n+3) , n ≠ -3,-2
@Spring Allergies, statements such as "I'm not very good at math, but I feels as though C would be your best bet" serve absolutely no purpose and do not help at all.
If you don't know what you are doing, please don't answer any student's questions.
Math is not a subject where you "feel" for correct answers.
= (n+2)(n+1)/( (n+3)(n+2)) - 2n/(n+3)
= (n+1)/(n+3) - 2n/(n+3) , now you have a common denominator
= (n+1 - 2n)/(n+3)
= (1 - n)/(n+3) , n ≠ -3,-2
@Spring Allergies, statements such as "I'm not very good at math, but I feels as though C would be your best bet" serve absolutely no purpose and do not help at all.
If you don't know what you are doing, please don't answer any student's questions.
Math is not a subject where you "feel" for correct answers.
Answered by
Beast
Roasted
Answered by
Bruh
Lmao he went off
Answered by
Anonymous
damn.
Answered by
lerry
broski said that back in 2019
Answered by
Destieltrash
2022 and springallergies still never recovered
Answered by
jay
2023 and he still aint recover
Answered by
mimi
well damn
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