Asked by Elena bug
The diagram below shows the contents of a jar from which you select marbles at random.
A. what is the probability of selecting a red marble, replacing it, and then selecting a blue marble?
B.what is the probability of selecting a red marble, setting it aside, and then selecting a blue marble?
C.are the answers from (a) and (b) the same? why or why not?
A. what is the probability of selecting a red marble, replacing it, and then selecting a blue marble?
B.what is the probability of selecting a red marble, setting it aside, and then selecting a blue marble?
C.are the answers from (a) and (b) the same? why or why not?
Answers
Answered by
plese help
if i help you will tou help me
Answered by
Elena bug
yeah sure!
Answered by
plese help
k perfect view mine and i will veiw yours
Answered by
Elena bug
did you ask one recently?
Answered by
plese help
propaganda is often used by
A. scientist
B. educators
C. individuals
D. governments
A. scientist
B. educators
C. individuals
D. governments
Answered by
Elena bug
Im pretty sure its D
Answered by
plese help
thank you!
i need to see the digram for this thogh
i need to see the digram for this thogh
Answered by
Elena bug
it won't let me post it
Answered by
Andrew
@bot What is the probability of selecting a red marble, replacing it, and then selecting a blue marble? Show your work.
What is the probability of selecting a red marble, setting it aside, and then selecting a blue marble? Show your work.
Are the answers to parts (a) and (b) the same? Why or why not?
What is the probability of selecting a red marble, setting it aside, and then selecting a blue marble? Show your work.
Are the answers to parts (a) and (b) the same? Why or why not?
Answered by
Bot
To solve the problem, we need to know the number of red marbles (R), the number of blue marbles (B), and the total number of marbles (T) in the jar. Let's assume that there are 5 red marbles, 3 blue marbles, and 8 marbles in total.
A. Probability of selecting a red marble, replacing it, and then selecting a blue marble:
P(RB) = P(R) × P(B) = (5/8) × (3/8) = 15/64 ≈ 0.234
B. Probability of selecting a red marble, setting it aside, and then selecting a blue marble:
P(RB) = P(R) × P(B|R) = (5/8) × (3/7) = 15/56 ≈ 0.268
C. The answers from parts (a) and (b) are not the same because in part (a) the red marble is replaced after it is chosen, while in part (b) it is not. Therefore, the probability of selecting a red marble decreases in part (b) because one red marble has already been removed from the jar. This affects the conditional probability of selecting a blue marble given that a red marble has already been chosen.
A. Probability of selecting a red marble, replacing it, and then selecting a blue marble:
P(RB) = P(R) × P(B) = (5/8) × (3/8) = 15/64 ≈ 0.234
B. Probability of selecting a red marble, setting it aside, and then selecting a blue marble:
P(RB) = P(R) × P(B|R) = (5/8) × (3/7) = 15/56 ≈ 0.268
C. The answers from parts (a) and (b) are not the same because in part (a) the red marble is replaced after it is chosen, while in part (b) it is not. Therefore, the probability of selecting a red marble decreases in part (b) because one red marble has already been removed from the jar. This affects the conditional probability of selecting a blue marble given that a red marble has already been chosen.
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