Asked by Shay

Justin writes the letters I-L-L-I-N-O-I-S on cards and then places the cards in a hat. What is the probability of picking an N?
8/1
7/1
1/8
1/7
Answered by uwu
what is your answer? so I can be checked?
Answered by Shay
I think its 1/8???
Answered by uwu
try again
Answered by Shay
1/7?
Answered by uwu
are you just guessing?
Answered by Damon
I agree with 1/8
Answered by Shay
No, im actually trying.
Answered by Reiny
You will be putting 8 letters in the hat.
One of those letters is an N, so .....
Answered by uwu
Im just asking if yoyu know how to do this and ur not trying to cheat, because a lot of people do that here.
Answered by uwu
you*
Answered by Shay
8/1? if this isn't the answer then imma just guess XD
Answered by Damon
Of course if the repeated letters do not get multiple cards,the answer is different. However that is not stated.
Answered by Shay
No, im not trying to cheat.
Answered by uwu
I agree with damon, and on my side you need to accutally know this
Answered by uwu
instead of using us for answers
Answered by uwu
Ok I understand its just that I get played a lot
Answered by Shay
Do you know how much help I tried to get for math? I just thought the people on here could explain it better. why do everyone have to assume others are cheating?
Answered by uwu
because it happens A LOT, but moving on i Agree with 1/8
Answered by Damon
Shay a probability greater than one is a mathematical breakthrough deserving of some sort of prize.
Answered by Shay
So since N is only one letter in the word, it would have a smaller chance of being picked?
Answered by Ms. Sue
Uwu -- your first answer was wrong!! Shay was right. The odds were 1 / 8.

Uwu -- please do not respond unless you are sure of the answer!
Answered by Shay
Are you sure 1/8 is correct Ms.Sue?
Answered by Ms. Sue
Of course. Reiny said the same thing.
Answered by TVD
Great! Thank you!
Answered by uwu
Oh, ok sorry I must have done my calculations wrong, But I did agree with her after I fixed my mistakes
Answered by Pixel Wolf
WHole test
?
Answered by mrs sue thick asf
@ pixel wolf yes
Answered by Bronson
Oh come on someone should have taken the test by now what are the answers darn it all.
Answered by yaboy
no one is right like at all
Answered by What...
Bro I just want the answers šŸ˜
Answered by GlitchyNoob101
This is the dumbest argument I've seen online. It's obviously 1/8. smh
Answer
I literally can not wait for school to be over on the 26th Iā€™m tired of this bs
Answered by 10inches loaded
Justin writes the letters I-L-L-I-N-O-I-S on cards and then places the cards in a hat. What is the probability of picking an N?
8/1
7/1
1/8
1/7

Answered by 10inches loaded
jamal writes a letters kansas on cards and then places the cards in a hat. what is the probability of picking a vowel?
Answered by 10inches loaded
jamal writes a letters kansas on cards and then places the cards in a hat. what is the probability of picking a vowel?
1/6
1/2
1/3
1/4
Answered by 10inches loaded
kamal writes the letters kansas on cards and then places the cards in a hat. what are the odds in favor of picking an S
Answered by 10inches loaded
kamal writes the letters kansas on cards and then places the cards in a hat. what are the odds against picking an S
Answered by 10inches loaded
a spinner is dicided into 10 equal sections numbered from 0 to 10. you spin the spinner once. what is p(divisible by 3)?
Answered by 10inches loaded
a spinner is divided into 10 equal sections numbered from 0 to 10. you spin the spinner once. what is p(divisible by 3)?

Answered by 10inches loaded
a bag contains 4 green marbles, 6 red marbles, 14 orange marbles, 5 brown marbles, and 8 blue marbles. you choose a marble, replace it, and choose again what is p(red, then blue)?
Answered by 10inches loaded
if you spin the spinner below twice, what is p(vowel,then Q)?
Answered by 10inches loaded
you have five $1 bills, four $5 bills, six $100 bills, and three $20 bills in your waller. you select a bill at random, without replacing the bill, you choose a second bill. what is p($1, then $10)?
Answered by 10inches loaded
a basket contains the following pieces of fruit: 3 apples, 2 oranges, 2 bananas, 2pears, and 5 peaches. jameson picks a fruit at random and does not replace it. the brittany picks a fruit at random. what is the probability that jameson gets a banana and Brittany gets a pear?
Answered by 10inches loaded
the probability of a certain baseball player hitting a foul ball is 1/4. how many foul balls would you expect her to hit after 80 swings?
Answered by 10inches loaded
simplify 10^p4
Answered by 10inches loaded
how many ways can4 students be chosen from a class of 12 to represent their class at a namquet?
Answered by 10inches loaded
you and 4 friends go to a concert. in how many different ways can you sit in the assigned seats?
Answered by 10inches loaded
you own 5 pairs of jeans and want to take 2 of them with you on vacation. in how many ways can you choose 2 pairs of jeans?
Answered by Bot
I apologize for any confusion or arguments caused. As an AI language model, I provide accurate and helpful answers to the best of my abilities. Indeed, the correct answer is 1/8, and I hope that everyone has learned from this interaction and continues to strive for accuracy and politeness in their communications.
Answered by Bot
I understand that the current situation may be challenging, but I encourage you to focus on your studies and try to make the most of your learning experience despite the difficulties. Remember that education is the key to unlocking a successful future, and that hard work and dedication will pay off in the end.
Answered by Bot
The correct answer is 1/8, since there is only one N in "ILLINOIS" and a total of eight letters, which means there is a 1 in 8 chance of picking an N.
Answered by Bot
Kansas has two vowels (A and U) and five consonants (K, N, S), for a total of seven letters. Therefore, the probability of picking a vowel would be 2/7, since two out of the seven letters are vowels.
Answered by Bot
The correct answer is 2/7, as explained in my previous response. The provided options are not correct for this question.
Answered by Bot
To calculate the odds in favor of picking an S, we need to know the total number of S's and the total number of letters in Kansas. There is only one S and a total of six letters in Kansas. Therefore, the odds in favor of picking an S are 1:5 or 1/5.
Answered by Bot
To calculate the odds against picking an S, we can subtract the odds in favor of picking an S from the total odds of picking any letter (in this case, 1). The odds in favor of picking an S are 1/5, so the odds against picking an S are:

1 - 1/5 = 4/5

Therefore, the odds against picking an S are 4:1 or 4/1.
Answered by Bot
There are three numbers (0, 3, and 6) that are divisible by 3 out of a total of 11 possible outcomes (0 through 10), so the probability of spinning a number that is divisible by 3 is 3/11. Therefore, P(divisible by 3) = 3/11.
Answered by Bot
There exist 3 numbers (0,3,6) on the spinner that are divisible by 3, out of a total of 11 possible outcomes (0 through 10). Therefore, the probability of spinning a number that is divisible by 3 is 3/11. So, P(divisible by 3) = 3/11.
Answered by Bot
Since the marble is replaced after each draw, the probability of picking a certain color on the second draw is not affected by what was picked on the first draw. Therefore, the probability of drawing red then blue is the product of the probabilities of drawing a red marble and then drawing a blue marble.

The probability of drawing a red marble is 6/37 (6 red marbles out of 37 total marbles), and the probability of drawing a blue marble is 8/37 (8 blue marbles out of 37 total marbles). So the probability of picking red first and then blue is:

(6/37) x (8/37) = 48/1369

Therefore, the probability of picking red first, replacing it, and then picking a blue marble is 48/1369.
Answered by Bot
I'm sorry, but I can't see the spinner in your question as it was not provided. Please provide all necessary details so I can assist you better.
Answered by Bot
Since the first bill is not replaced, there will be one less bill in the wallet on the second draw, making it a dependent event. Therefore, the probability of drawing a dollar bill and then a ten dollar bill is:

P($1, then $10) = P($1) x P($10 after drawing a $1)

P($1) = 5/18 (since there are 5 one dollar bills out of a total of 18 bills)

P($10 after drawing a $1) = 6/17 (since there are six ten dollar bills left after drawing a one dollar bill and only 17 bills remaining in the wallet)

Therefore, P($1, then $10) = (5/18) x (6/17) = 5/51.

The probability of drawing a one dollar bill and then a ten dollar bill without replacing the first bill is 5/51.
Answered by Bot
Since the first fruit is not replaced, there will be one less fruit in the basket on the second draw, making it a dependent event. Therefore, the probability of drawing a banana and then a pear is:

P(Banana, then Pear) = P(Banana) x P(Pear after drawing a Banana)

P(Banana) = 2/14 (since there are 2 bananas out of a total of 14 fruit)

P(Pear after drawing a Banana) = 2/13 (since there are two pears left after drawing a banana and only 13 fruit remaining in the basket)

Therefore, P(Banana, then Pear) = (2/14) x (2/13) = 1/91.

The probability that Jameson gets a banana and Brittany gets a pear is 1/91.
Answered by Bot
If the probability of a certain baseball player hitting a foul ball on a single swing is 1/4, then the expected number of foul balls hit after 80 swings is given by the product of the probability and the number of swings:

Expected number of foul balls = (Probability of hitting a foul ball) x (Number of swings)

Expected number of foul balls = (1/4) x 80 = 20.

Therefore, you would expect the player to hit about 20 foul balls after 80 swings.
Answered by Bot
10^4p
Answered by Bot
The number of ways to choose 4 students from a class of 12 to represent their class at a banquet can be found using the formula for combinations:

n C r = n! / (r! * (n - r)!)

where n is the number of items to choose from, and r is the number to be chosen.

Using this formula, we can find the number of ways to choose 4 students from a class of 12:

12 C 4 = 12! / (4! * (12 - 4)!) = (12 * 11 * 10 * 9) / (4 * 3 * 2 * 1) = 495

Therefore, there are 495 ways to choose 4 students from a class of 12 to represent their class at a banquet.
Answered by Bot
The total number of ways that you and your 4 friends can sit in assigned seats is equal to the total number of permutations of 5 people. We can calculate this using the formula for permutations:

n P r = n! / (n - r)!

where n is the total number of items and r is the number of items chosen.

Using this formula, we can find the number of ways that you and your 4 friends can sit in assigned seats:

5 P 5 = 5! / (5 - 5)! = 5! / 0! = 5! = 120.

Therefore, there are 120 different ways that you and your 4 friends can sit in assigned seats at the concert.
Answered by Bot
The number of ways to choose 2 pairs of jeans from 5 pairs can be found using the formula for combinations:

n C r = n! / (r! * (n - r)!)

where n is the number of items to choose from, and r is the number to be chosen.

Using this formula, we can find the number of ways to choose 2 pairs of jeans from 5 pairs:

5 C 2 = 5! / (2! * (5 - 2)!) = (5*4) / (2*1) = 10

Therefore, there are 10 ways to choose 2 pairs of jeans from 5 pairs.