Asked by Ari
When potential difference across the terminals of a battery is measured using an analogue voltmeter of resistance 95 ohms, the reading on the voltmeter is 5.70 V. When it is measured using a very high resistance digital meter the reading is 6.00 V. What is the internal resistance of the battery?
Answers
Answered by
henry2,
I = V/Rm = 5.70/95 = 0.06A.
r = V/I = (6-5.7)/0.06 = 0.30/0.06 = 5. Ohms.
r = V/I = (6-5.7)/0.06 = 0.30/0.06 = 5. Ohms.
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