v = <(-5/2),(23/7)>
||v|| = √((5/2)^2 + (23/7)^2)
how ever did you get v=<1,1>?
Find the component form and the magnitude of the vector v. (Express the components of v as fractions. Round the magnitude of v to four decimal places.)
Initial Point: (7/2, -3)
Terminal Point: (1, 2/7)
v=< , >
||v||=
the answers i got are:
v=<1,1>
||v||=(-5/2),(23/7)
but my online assignment says that both of my answers are wrong
2 answers
thanks oobleck