Asked by Jean
A beach ball rolls off a cliff and onto the beach. The height, in feet, of the beach ball can be modeled by the function h(t)=64–16t2, where t represents time, in seconds.
What is the average rate of change in the height, in feet per second, during the first 1.25 seconds that the beach ball is in the air?
I got the answer 39 is that correct?
What is the average rate of change in the height, in feet per second, during the first 1.25 seconds that the beach ball is in the air?
I got the answer 39 is that correct?
Answers
Answered by
oobleck
h(1.25) = 39
h(0) = 64
avg rate of change is totaldisplacement/totaltime = (39-64)ft/1.25s = -20ft/s
you only found the displacement, not the rate of change.
h(0) = 64
avg rate of change is totaldisplacement/totaltime = (39-64)ft/1.25s = -20ft/s
you only found the displacement, not the rate of change.
Answered by
Jean
Oh okay thank you but I got the anwser 20 instead of negative -20
Answered by
Jean
Nvm I did the calculations wrong you were right. Thanks again for your help
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.