Question
A 15kg tuna fish moving horizontally to the right at 5m/s swallows a 2kg fish that is swimming to the left at 7.5 m/s .What is the speed of the tuna fish immediately after,if the force exerted on the fish by the water can be neglected?
Answers
conserve momentum
15(5) + 2(7.5) = 17v
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15(5) + 2(7.5) = 17v
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