Asked by Abe
A Petrol Engine Raises 200litres Of Water In A Well From A Depth Of 7m In 6 Sec.What Is The Power Of The Engine?
Answers
Answered by
R_scott
a litre of water has a mass of one kg
power = work / time = m g h / t = 200 * 9.8 * 7 / 6 ... watts
power = work / time = m g h / t = 200 * 9.8 * 7 / 6 ... watts
Answered by
Abe
Given Here
1litre=1kg,M=200kg,H=7m,T=6sec,P=W/T=mgh/t=200*9.8*7/6=2286.66
1litre=1kg,M=200kg,H=7m,T=6sec,P=W/T=mgh/t=200*9.8*7/6=2286.66
Answered by
Benhur solomon
p=w/t
W=Mgh
1litir=1kg
200L=200kg
W=200kg*9.81m/s^2*7m
W=13734j
P=13734/6
P=2289watt
W=Mgh
1litir=1kg
200L=200kg
W=200kg*9.81m/s^2*7m
W=13734j
P=13734/6
P=2289watt
Answered by
abeje
i give the answer step by step
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