ok, I will do g(g(-1)), you do the last one
g(g(-1))
= g(-3)
= 3(-3) = -9
I have these algebra problems that I have been stuck on for over a week, and I'm beginning to fall behind. Any help will be much appreciated.
I am told to compute the following:
Let g(x) = 3x, and h(x) = x^2 + 1.
The first one was g(-1), and I got g(-1)=3(-1)=-3.
I'm now stuck on what g(g(-1)) and g(g(g(-1))) would be.
4 answers
Thank you, I appreciate it!
Am I on the right track?
g(g(g(-1)))
= g(-9)
= 9(-9)(-9)=729
g(g(g(-1)))
= g(-9)
= 9(-9)(-9)=729
I'm going to try this again on my own, believe I did this wrong.
1 answer