Asked by Jayson
Simplify, stating any restrictions on the variables: x+1/2x^2-7x+6 - x-3/2x^2-x-3
Answers
Answered by
oobleck
assuming the usual carelessness with parentheses, I get
(x+1)/(2x^2-7x+6) - (x-3)/(2x^2-x-3)
= (x+1)/((x-2)(2x-3)) - (x-3)/((x+1)(2x-3))
Since division by zero is undefined, x=2, 3/2, -1 are excluded from the domain.
Combining over a common denominator yields
= ((x+1)^2 - (x-3)(x-2))/((x-2)(x+1)(2x-3))
= (7x-5)/((x-2)(x+1)(2x-3))
The three excluded values are still evident.
(x+1)/(2x^2-7x+6) - (x-3)/(2x^2-x-3)
= (x+1)/((x-2)(2x-3)) - (x-3)/((x+1)(2x-3))
Since division by zero is undefined, x=2, 3/2, -1 are excluded from the domain.
Combining over a common denominator yields
= ((x+1)^2 - (x-3)(x-2))/((x-2)(x+1)(2x-3))
= (7x-5)/((x-2)(x+1)(2x-3))
The three excluded values are still evident.
Answered by
Jayson
@ooblect are there any restrictions?
Answered by
Jayson
@oobleck
Answered by
oobleck
yes. I said which real numbers are excluded from the domain.
Uhhh .. those are restrictions, right?
Uhhh .. those are restrictions, right?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.