Asked by Anonymous
Two cards are drawn without replacement from a shuffled deck of 52 cards. What is the probability that the first card is a black ace and the second card is a red ace?
Select one:
a. 1/1300
b. 1/663
c. 1/2704
Select one:
a. 1/1300
b. 1/663
c. 1/2704
Answers
Answered by
ThatgirlJayden
here's only one ace of clubs. Since the ace of clubs is black and there are 26 black cards, that leaves 25 black cards remaining for the second draw. So the probability that the first card is an ace of clubs and the second is black is:
1/52 x 25/51
1/52 x 25/51
Answered by
oobleck
there are two black aces and 2 red aces. So
P = 2/52 * 2/51 = 1/663
P = 2/52 * 2/51 = 1/663
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